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Unknown KHP
Determination
Diego J. Gavia
Chemistry 116AL – W06
Tuesday-Thursday 6-10 PM
Sample ID: KHP ??
Group Members: Jannice
Experimental Methods:
The unknown
KHP sample and 3.0599 grams of KHP standard were added to individual weighing
bottles. Both weighing bottles containing the samples were placed in an oven at
a temperature of 110 ºC for two hours to completely dry the samples. After two
hours, the unknown KHP sample and KHP standard were place in the desiccator to
prevent the sample from absorbing moisture. Two liters of distilled water were
boiled for 10 minutes to remove any carbon dioxide. To speed up the cooling
process, the boiled distilled water was place in a bath consisting of cold
water and ice. Once the distilled water was cooled to room temperature, 3.59 mL
of 50% NaOH were carefully added to 960 mL of distilled water by not disturbing
the precipitates at the bottom of the bottle, which resulted in a solution of
~0.1 M NaOH. The resulting solution was transferred to a polyethylene bottle.
The other liter of water was added to a glass labeled bottled. A 50 mL burette
was clean and filled the ~0.1 M NaOH solution. Three titration blanks were
prepared in Erlenmeyer flasks by adding two drops of phenolphthalein as an
indicator and 100 mL of distilled water to each. The blanks were titrated until
the solutions turned pale pink by the ~0.1 M NaOH solution. Three standard KHP
solutions were prepared by adding .7301g KHP, .7101g KHP and .7310g KHP
accordingly along with two drops of phenolphthalein and 50 mL of distilled
water. The standard KHP solutions were titrated until the solutions turned pale
pink by the ~0.1 M NaOH solution. Finally, three unknown KHP solutions were prepared
by adding 1.0263g unknown, .6084g unknown and .8116g unknown accordingly along
with two drops of phenolphthalein and 50 mL of distilled water. The unknown KHP
solutions were titrated until the solutions turned pale pink by the ~0.1 M NaOH
solution.
Results:
Table 1. Blank titration results.
Volume of Water Total Volume of NaOH solution
Trial 1 100 mL
.60 mL
Trial 2 100 mL
.40 mL
Trial 3 100 mL
.60 mL
Final Result
(.533 mL of NaOH solution)
Table 2. KHP standard titration results.
Volume
of Water Mass Total
Volume of NaOH solution
Trial 1 50 mL .7301g 48.95 mL
Trial 2 49 mL .7101g 47.73 mL
Trial 3 48.7 mL .7310g 49.21 mL
Final Result
(.07367 ± .002113732 M NaOH )
Table 3. KHP unknown titration results.
Volume
of Water Mass Total
Volume of NaOH solution
Trial 1 50 mL 1.0263g 41.13 mL
Trial 2
46.5 mL .6084g 24.64 mL
Trial 3 50 mL .8116g 32.99 mL
Final Result
(59.41 ± 2.02 % wt KHP)
Discussion:
To determining the mass
percentage of an unknown KHP sample, several steps as well as calculations were
required. Boiling distilled water for this experiment was crucial, since carbon
dioxide had to be removed. Nonetheless, while the distilled water was cooling
in the ice bath, carbon dioxide could have tainted the water sample. The KHP
samples had to be dried at 110 ºC to remove all the moisture but in reality the
KHP samples were exposed to moisture while weighing them. The titration process
was difficult and decisive. Since NaOH reacts with glass, solutions of NaOH
stored in glass equipment such as burettes and beakers for long periods of time
were not dependable and had to be disposed of. Therefore, working quickly and working
carefully were key in this experiment.
Truly
Dr. SuperCatBoy
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| | Posted 1/26/2006 12:15 AM - 57 Views
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